trig
posted by sol .
solve the equation
2sin^2X  3sinX= 1

2 sin^2 x  3sinx + 1 = 0
(2sinx  1)(sinx 1) = 0
sinx = 1/2 or sinx = 1
x = 30 degrees or 150 degrees or x = 90 degrees
in radians x = π/6, 5π/6, π/2
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