Math CAN SOMEONE PLEASE CHECK MY WORK?
posted by KiKi .
7x+5y=26
x=286y
solve using substitution
okay so then 19642y+5y=26
then combined like terms so
196+37y=26
37y=222
y=6 is this part correct?

You are correct KiKi. y= 6

I believe that is a +6 and most would prefer that you put in another step.
like so:
7(28  6y) + 5y = 26, then
196 42y + 5y = 26
37y = 222
y=+6 
You are correct. The answer is 6.
7(286y)+5y=26
19642y+5y=26
37y=222
37y/37=222/37
y=6 
The answer is not 6, it is +6.
Both Louise and Michael subtracted incorrectly.
7(286y) + 5y = 26
19642y + 5y = 26
(42y + 5y is 37y; therefore)
196  37y = 26196 = 222
37y= 222 and
y=(222/37) = +6.
Solve for x now.
x = 286y
x = 286(+6)
x = 2836
x  8.
Now substitute x = 8 and y = +6 into the first equation.
7x + 5y = 26
7(8) + 5(+6) = 26
56 + 30 = 26
26 = 26
Substitute 6 and it won't work. 
0y55y=6y626
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