# chm152

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Consider the following equilibrium:

5.0 moles of are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium.

a. 0

b. 1.0

c. 2.0

d. 3.0

e. 4.0

• chm152 -

Ami--Are you taunting those trying to help? ;-).
You didn't provide the equilibrium reaction. also look at your first post today. It isn't complete either.

• chm152 -

PCL5(g)=PCL3(g)+CL2(g)

5.0 moles of are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium.

a. 0

b. 1.0

c. 2.0

d. 3.0

e. 4.0

• chm152 -

PCL5(g)=PCL3(g)+CL2(g)

5.0 moles ofWHAT are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of WHAT is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium.

• chm152 -

PCL5(g)=PCL3(g)+CL2(g)

5.0 moles of PCL5 are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium.

a. 0

b. 1.0

c. 2.0

d. 3.0

e. 4.0

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