Math
posted by B.B. .
Write an equation of the line containing the given point and perpendicular to the given line.
(8,6); 3x+5y=8. The equation of the line is y=
Here is what I have: 3x+5y=8 5y=3x+8
y= 3/5(x)+8/5 y=5/3(x)=b 5=5/3(5)+b
5=25/3+b 15=25+3b
40=3b b= 40/3= 13 1/3 y= 5/3(x)13 1/3
Is this correct? If not could you please show me where I went wrong? Thanks.

you should know that the slopes of perpendicular lines are opposite reciprocals of each other, so shouldn't the new equation look like
5x  3y = c ?
plug in the point (8,6)
40 + 18 = c = 58
so 5x  3y = 58 , ALL DONE!
(By the way, I did not even make an effort to read your calculations. Since they just run across the page, I can't decide where one statement ends and the next one repeats.)