trig

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find the exact value given that cosA=(1/3) in quad I, sin B=(-1/2) in quad 4, and sin C=(1/4) in quad 2

sin(A-B)?

  • trig -

    if cosA = 1/3 in I, then sinA = √8/3 using Pythagoras
    if sinB= -1/2 in IV, the cosB = √3/2

    sin (A-B) = sinAcosB - cosAsinB
    = (√8/3)(√3/2) - (1/3)(-1/2)
    = (√24 + 1)/6

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