posted by .

if y=sec^(3)2x, then dy/dx=

my answer is 6 sec^3 2xtan 2x but im not sure if that is right. ?
Can someone show me if i did it correct.

  • Math-Derivatives. -

    good job

  • Math-Derivatives. -

    Sorry to bother you, can you explain the steps to me, so I can see the work and check my work. I thought i had done it wrong, I started my work and then guessed.

  • Math-Derivatives. -

    write it as

    y = (sec (2x))^3
    now use the chain rule ...

    y' = 3(sec (2x)^2 (derivative of sec(2x))
    = 3(sec (2x)^2(sec (2x))tan (2x))(2)
    = 6(sec (2x))^3 tan (2x)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct?
  2. statistics

    The time (sec) that it takes a librarian to locate an entry in a file of records on checked-out books has an exponential distribution with lambda symbol=0.5. a)What proportion of all location times are less than 20 sec?
  3. calculus

    i have to integrate using u substitution, but i am not sure if i did it correct. çtan^3(5x)sec^2(5x)dx u=5x du=5dx 1/5du=dx 1/5çtan^3(u)sec^2(u)du 1/5tanusec^2u+c 1/5tan(5x)sec^2(5x)+c
  4. Integration?

    Use the derivatives of sinx and cosx to show that d/dx [tanx] = sec^2 and that d/dx [secx]=sec^2xsinx. Hence evaluate ∫ [1 + sinx]/[cos^2x] dx limit from 0 to pi I know the first part of the question, i'm not sure how i should …
  5. Calculus - not sure if my work is correct?

    A 15ft ladder leans against a building and its base starts to slide down the wall. The base is moving at a rate of 5ft/sec when the base is 9ft from the wall. How fast is the top of the ladder moving at this moment?
  6. Calculus 12th grade (double check my work please)

    2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents …
  7. calculus

    Did I do this problem right? Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x
  8. calculus (check my work please)

    Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] …
  9. Calculus AP

    I'm doing trigonometric integrals i wanted to know im doing step is my answer right?
  10. math

    Determine all the possible values of x where 0 deg is more than or equal to x and x is more or equal to 360 deg such that i'm not sure the solution, please correct it and how to find the x value, 2 tan x - 1 = cot x solution: (sec …

More Similar Questions