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chemistry

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A 4.90 g nugget of pure gold absorbed 255 J of heat. What was the final temperature of the gold if the initial temperature was 24.0°C? The specific heat of gold is 0.129 J/(g·°C).

  • chemistry -

    q = mass Au x specific heat Au x (Tfinal-Tinitial)

  • chemistry -

    463.5342

  • chemistry -

    YOU CAN USE ALGEBRA!
    energy absorbed=given grams x specific heat x (unknown final temperature-initial temp)
    SO:
    255=4.90(.129)(x-24)
    255=0.6321(x-24)
    DIVIDE BOTH SIDES BY .6321
    .6321(255)=(.6321(x-24))/,6321
    403.42 = x-24
    +24 +24
    ----------------
    x=427.42

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