# College Chemistry

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Calculate the ratio of NaF to HF required to create a buffer with pH=3.95.

Also, can you please explain in a nutshell the whole concept of buffers?

Thanks!

• College Chemistry -

Never mind, I figured it out.

• College Chemistry -

what was the anwer?

• College Chemistry -

pH=pKa + log(base/acid)
3.95=3.465 + log(base/acid)
.494=log(base/acid)
10^.494
3.1

• College Chemistry -

thanks!!

• College Chemistry -

wait what? that's not right the -log(.494) = 2.02

• College Chemistry -

john the answer is right 3.1; u have to key on ur calc 2nd key then log key then the (^)key :) to get that answer.

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