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How do I convert the polar equation r - 3cos(theta) = 5sin to cartesian equation form?

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see the bottom part of my reply to

http://www.jiskha.com/display.cgi?id=1269266887

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r - 3cosØ = 5sinØ
√(x^2 + y^2) - 3x/r = 5y/r
√(x^2 + y^2) = 5y/r + 3x/r
√(x^2 + y^2) = (5y + 3x)/r
√(x^2 + y^2) = (5y + 3x)/√(x^2 + y^2)
cross multiply
x^2 + y^2 = 5y + 3x

which looks like the equation of a circle to me

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