how many gram of potassium bromide can be made from 13.7 grams of potassium and unlimited bromide

Write the equation and balance it.

Convert 13.7 g K to moles. moles = grams/molar mass.

Using the coefficients in the balanced equation, convert moles K to moles KBr.

Now convert moles KBr to grams. grams = moles x molar mass.

how many grams of potassium is needed to make 75.5 grams of potassium bromide

To determine the grams of potassium bromide that can be made from 13.7 grams of potassium, we need to know the molecular formula of potassium bromide and the molar masses of potassium and bromide.

The molecular formula of potassium bromide is KBr, which means it consists of one potassium atom (K) and one bromide atom (Br).

The molar mass of potassium (K) is approximately 39.1 grams/mol, and the molar mass of bromide (Br) is approximately 79.9 grams/mol.

Since the molar ratio between potassium and potassium bromide is 1:1, we can use the molar mass of potassium to calculate the number of moles of potassium (13.7 grams / 39.1 grams/mol).

Number of moles of potassium = 13.7 g / 39.1 g/mol ≈ 0.350 moles

Since the molar ratio between bromide and potassium bromide is also 1:1, the number of moles of bromide is the same as the number of moles of potassium.

Number of moles of bromide = 0.350 moles

To determine the mass of potassium bromide, we need to multiply the number of moles of bromide by the molar mass of potassium bromide.

Mass of potassium bromide = Number of moles of bromide × molar mass of potassium bromide

Mass of potassium bromide = 0.350 moles × (39.1 g/mol + 79.9 g/mol)

Mass of potassium bromide ≈ 31.85 grams

Therefore, approximately 31.85 grams of potassium bromide can be made from 13.7 grams of potassium and unlimited bromide.

41.7 g KBr