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let f(x)=sqrt of 121-x^2
a. graph the function
b. state the domain and range of f(x)

  • math -

    y=sqrt[121-x^2]
    a. graph the function
    b. state the domain and range of f(x)

    when x = +11, y = 0
    when x = -11, y = 0

    when x = 0, y = 11 never gets bigger

    If |x| > 11 , y is imaginary

    so parabola is upside down with vertex at (0,11) and zeros at +and - 11

    It never goes below the y axis
    It never goes above y = 11
    That defines the range and
    x is from -11 to + 11 defining the domain

  • math -

    so the domain is [-11,11)

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