Calculus
posted by sh .
Find the derivative of y with respect to x:
y=3sin^4(2x)^1
y=[3sin(2x)^1]^4
y'=4[3sin(2x)^1]^3 (3cos(2x)^1)(1) (2x)^2
y'=[12cos(2x)^1][3sin^3(2x)^1][2x]^2
but the answer does not have a 3 in front of sin. What happened to the 3?
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