10th grade
posted by boom .
A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow. What is the approximate height of the tree to the nearest foot?

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Because of similartriangle geometry rules, the ratio of shadow length to the height of the object casting the shadow is a constant. If the tree height is x,
25/x = 9/6
Solve for x. 
37.5

Its 47 feet.

what?

25/9=x/6
...
(25*2)/3
=50/3
=16.666666..... feet! 
The ques tion is wrong...
it ain't 26/x=9/6
its 25/9=x/6 
37.5

A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow. What is the approximate height of the tree to the nearest foot?
25/x = 9/6 (where 25 is the tree's shadow, x is the unknown height of the tree, 9 is the man's shadow and 6 is the man's height)
solve for x
cross multiply 25(6) = (9)x
150 = 9x
x = 150/9
do the division
x = 16.6
the tree is 16.6 feet or about 17 feet tall 
A tree that is 100 feet tall casts a shadow that is 150 feet long. Determine the angle at which the rays of the sun hit the ground, to the nearest degree.

9.75 feet

Math is shhhittt

i want an answer of this...plz help me... a vertical stick of 30m long casts a shadow 15m long on the ground. at the same time a tower casts a shadow 75 m long on the ground. what is the height of the tower?

a telephone pole casts a 36 foot shadow nearby a 6 foot man casts an 8 foot shadow how tall is the telephone pole

??????

6/x = 9/25
9x = 150
x = 150/9
x = 16.666.../16.7/17 feet 
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