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chemistry

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At 2200 degrees celsius,kp=0.050 for the reaction: n2(g)+O2(g) ->2NO(g)
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What is the partial pressure of NO in equilibrium with N2 and O2 that were placed in a flask at initial pressures of .80 and .20 atm, respectively?

  • chemistry -

    N2 + O2 ==> 2NO

    Kp = pNO^2/pN2*pO2 = 0.05

    Set up an ICE chart.
    initial:
    NO = 0
    N2 = 0.8
    O2 = 0.2

    change:
    NO = 2x
    N2 = -x
    O2 = -x

    equilibrium:
    NO = 2x
    N2 = 0.8-x
    O2 = 0.2-x
    Substitute into Kp and solve.
    Post your work if you get stuck.

  • chemistry -

    0.082

  • chemistry -

    0.1857

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