Math

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A man earned $ 3000 the first year he worked. If he received a raise of $ 400 at the end of each year,
what was his salary during the 15 th year?

A) $ 8600 B) None of these C) $ 5600 D) $ 9000

  • Math -

    3000+ 400n where n = # of year

    n=1 (first year) 3000+400n = 3000 +400(1) = 3400
    .
    .
    .
    .
    n= 15 (15th year) 3000+ 400(15) = 3000+ 6000 = 9000

    maybe this is rite?

  • Math -

    Thanks, I think this is correct. I n elp w/ the concepts.

  • Math -

    during 1st year = 3000
    during 2nd year = 3000 + 1(400)
    during 3rd year = 3000 + 2(400)
    .
    .
    during 15th year = 3000 + 14(400) = 8600

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