Math

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Write an equation of the line containing the given point and parellel to the given line.

(2,-6); 9x-5y=4

  • Math -

    rearranging the given line,
    y = (9/5)x - 4/5 (1)
    which has the form
    y = mx + b (2)
    where m is the slope and b is the y intercept.
    The new line would have the same slope to be parallel, so it would have the form:
    y = (9/5)x + b (3)
    to solve for b, input the given coordinates, obtaining:
    (-6) = (9/5)(2) + b
    rearrange and solve for b, then substitute back into equation (3)

  • Math -

    It looks like b = -30/5 -18/5 = -48/5
    So
    y = (9/5)x - 48/5
    (or 9x-5y=48)

    Check: when x = 2,
    y = 18/5 - 48/5 = -30/5 = -6
    Looks OK

  • Math -

    The new equation must be something like
    9x - 5y = c
    plug in the given point(2,-6)
    18 + 30 = c = 48

    all done : 9x - 5y = 48

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