calculus
posted by Bobby .
How do you prove that the total area of a fourpetaled rose r=sin2x is equal to onehalf the area of the circumscribed circle?

Use a polar coordinate integration to get the area inside the rose. The circumscribed circle area is, of course, pi, since rmax = 1
For the rose, the area is
S (1/2)r^2 dx
(for x integrated from 0 to 2 pi
= S (1/2)sin^2x dx
"S" denotes an integral sign.
=(1/2)[(x/2) (1/4)(sin2x)]@x=2pi 
(1/2)[(x/2) (1/4)(sin2x)]@x=0
= (1/2)*pi
qed
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