posted by Anonymous .
Determine the coordinates of the point on the curve representing the function f(x)=ln(2x-1) where the tangent is parallel to the line with equation 2x-5y=0
Thanks for any help!
The slope of the 2x -5y = 0 line is 2/5.
You are looking for a point on the f(x) curve where f'(x) = 2/5
f'(x) = 2/(2x -1) = 2/5
x = 3
f(x) = ln(5) = 1.60944