# precal

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find the exact value of the expression:
csc (tan^-1 ã3/3)

• precal -

Is this supposed to say,
csc (tan^-1 √3/3) ?

if so, then we have a triangle with opposite as √3 and adjacent as 3, which by Pythagoras gives a hypotenuse of √12

then csc (tan^-1 √3/3) = √12/√3 = √4 = 2

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