posted by Chelsea .
4.54 g of hydrazoic acid ( HN3 ) is added to water to make a final solution of 504 ml.
What is the pH of the solution ?
Use Ka = 1.90 × 10−5
HN3 + H2O ==> H3O^+ + N3^-
Convert 4.54 grams to moles and divide by volume in liters to obtain molarity. Set up an IC# chart and calculate H^+, then convert to pH.