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Approximate the equation's soultions in the interval (o, 2pi). If possible find the exact solutions.

sin 2x sinx = cosx

I do not know where to start.

• Pre-Cal -

Expand sin 2x using the identity:
sin2x=2sin(x)cos(x)
We'll get:
2cos(x)sin²(x)=cos(x)
Transpose left-hand-side to the right:
2cos(x)((1/2)-sin²(x))=0
So
cos(x)=0, or
sin²(x)=1/2
Solve for x in (0,2π) as specified.

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