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chemistry

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How many milliliters of .50 M NaOH solution are required to titrate 40.0 mL of a 0.10 M H2SO4 solution to an end joint?

  • chemistry -

    2NaOH + H2SO4 ---> Na2SO4 + 2H2O

    n = (Molarity)(vol)
    n= (0.10M)(0.04L)
    =0.004moles of H2SO4

    0.004molesH2SO4 * 2moles NaOH/1mole H2SO4
    = 0.008moles NaOH

    so M= n/v
    v=n/M
    = 0.008/0.50
    = 0.004L
    0.004*1000
    = 4.0 ml

  • chemistry--correction -

    Correction to response by Zoe
    2NaOH + H2SO4 ---> Na2SO4 + 2H2O

    n = (Molarity)(vol)
    n= (0.10M)(0.04L)
    =0.004moles of H2SO4

    0.004molesH2SO4 * 2moles NaOH/1mole H2SO4
    = 0.008moles NaOH

    so M= n/v
    v=n/M
    = 0.008/0.50
    OK to here.
    0.008 moles/0.50 L = 0.016 L or 16 mL.


    = 0.004L
    0.004*1000
    = 4.0 ml

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