# chemistry

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How many milliliters of .50 M NaOH solution are required to titrate 40.0 mL of a 0.10 M H2SO4 solution to an end joint?

• chemistry -

2NaOH + H2SO4 ---> Na2SO4 + 2H2O

n = (Molarity)(vol)
n= (0.10M)(0.04L)
=0.004moles of H2SO4

0.004molesH2SO4 * 2moles NaOH/1mole H2SO4
= 0.008moles NaOH

so M= n/v
v=n/M
= 0.008/0.50
= 0.004L
0.004*1000
= 4.0 ml

• chemistry--correction -

Correction to response by Zoe
2NaOH + H2SO4 ---> Na2SO4 + 2H2O

n = (Molarity)(vol)
n= (0.10M)(0.04L)
=0.004moles of H2SO4

0.004molesH2SO4 * 2moles NaOH/1mole H2SO4
= 0.008moles NaOH

so M= n/v
v=n/M
= 0.008/0.50
OK to here.
0.008 moles/0.50 L = 0.016 L or 16 mL.

= 0.004L
0.004*1000
= 4.0 ml

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