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aksed find the equation oft he parabola y=ax^2 + bx +c. there are four given clues
1) the y-intercept is (0,6)
2) the curve goes throuth (4,5)
3) the curve has aturning point at (2,3)
4) the line of symmetry is x=1

a)is it not possible for all four clues to be true together (why not?)
b)which combinations of clues enable you to find a set of values a,b and c?
c)find the resulting parabola for each successful combination

  • math -

    7+4+5-3+9-10+7-8

  • math -

    (a) If the curve has a "turning point" (minimum or maximum) at (2,3), its line of symmetry would have to be x=2.

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