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How much energy will be released when 11.11g of calcium chloride dissolves in 100 mL of water.
deltaHf of Ca 2+ (aq)=-543Kj/mol,
deltaHf of Cl 1-(aq) = -167Kj/mol

CaCl2(s) ==> Ca 2+(aq) + 2Cl 1-(aq)

  • Chemistry -

    See if this sounds reasonable to you.
    moles CaCl2 = 11.11/110.98 = 0.1 mole
    Ca = 0.1 mol
    Cl = 0.2 mol

    Ca = 543 kJ/mol x 0.1 mol = -54.3 kJ.
    Cl = 167 kJ/mol x 0.2 mol = -33.4 kJ.
    Total released = sum of the two.

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