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posted by Anonymous .
In the sequence: x+4y ; 2y+2 ;x ;y1, (consisting of 4 terms) the first three terms form an arithmetric progression, while the last three tern form a geometric sequence. Calculate the values of x and y. Answer(s) can be left in surd form.

maths 
Reiny
"the first three terms form an arithmetric progression"
so....
2y+2  (x+4y) = x  (2y+2)
which gives x = 2
"the last three tern form a geometric sequence"
so ...
x/(2y+2) = (y1)/x , but we know x = 2
2/(2y+2) = (y1)/2
I get y = ±√3
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