PHysics
posted by engmath .
The vector position of a 3.65 g particle moving in the xy plane varies in time according to the following equation.
r1 = <(3i+3j)t + 2jt^2>
At the same time, the vector position of a 5.60 g particle varies according to the following equation.
r2 = <3i  2it^2  6jt>
For each equation, t is in s and r is in cm. Solve the following when t = 2.90
(a) Find the vector position of the center of mass.
ihat__________ cm
jhat___________cm
(b) Find the linear momentum of the system.
ihat___________ gcm/s
jhat____________gcm/s
(c) Find the velocity of the center of mass.
ihat_________cm/s
jhat__________ cm/s
(d) Find the acceleration of the center of mass.
ihat____________cm/s2
jhat_____________cm/s2
(e) Find the net force exerted on the twoparticle system.
ihat___________ μN
jhat___________μN

Maybe someone could just explain to me how to solve for each part because I'm thoroughly confused. THANK YOU.
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