PreCal(Please check)
posted by Hannah .
1) Find the Asymptotes:
y = 2 sec 2pi x
pi/2b and 3pi/2b
pi/2(2pi) = pi/4 and 3pi/4
Is this correct?
2) Find the period and asymptotes:
y = 1/2 sec pi x / 2
b = pi/2 I do not know how to find the period of asymptotes for this one. My original answer was 1 for the period and pi and 3pi for the asymptotes.

No.
y = 2 sec 2pi x
when the argument is PI/2, or 3PI/2 of the secant function, it is inf
2PI x =PI/2
x= 1/4 or x= 3/4 is the x value of the asymptote.
2. PIx/2=PI/2 or 3PI/2
x=1 or x=3 is asympotes
period? here is a neat way to memorize finding frequency and period.
You should know this could also be written as sin w*x, where w(omega) is the angular frequency (2PI f) or 2PI/period
So where we have sec PIx/2
convert it PI*x/2=2PIx/2 * 1/period
period= 1/f= 1
Respond to this Question
Similar Questions

PreCalculuscheck answers
State the period and phase shift of the function y=4tan(1/2x + 3pi/8) a) 2pi, 3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, 3pi/8 Answer: d 2) What is the equation for the inverse of y=cos x+3: a) y=Arccos(x+3) b) y=Arccos x3 c) y=Arccos … 
Math
In the interval 0 </ x < 2pi, determine the equations of all asymptotes for the function y=tan x. a) x=0 b) x=pi/2 c) x=0, x=pi d) x=pi/2, 3pi/2 
PreCal(Please check)
Approximate the equation's solutions in the interval (0,2pi) sin2x sinx = cosx 2cos(x) (1/2sin^2x) = 0 Then I got 3pi/2, pi/2, pi/6 and 5pi/6 Then I substituted 03 and got 3pi/2 , 5pi/2 , 9pi/2 , pi/2, pi/6, 7pi/6, 13pi/6 , 19pi/6 … 
trig
I need to state the period and 2 consecutive asymptotes on the graph for the following questions. 1: y = 3 tan pi*x period: pi (? 
calculus
given the graph of f(x) = x sinx, 0<=x<=2pi assuming that a quantity y changes at a rate of y' = xsinx, find by how much it will increase or decrease over 3pi/2 <= x <= 2pi the area under the graph from 0 to pi/2 is 1 the … 
TRIG
I need to state the period and 2 consecutive asymptotes on the graph for the following questions. 1: y = 3 tan pi*x period: pi (? 
trig
Solve cos x1 = sin^2 x Find all solutions on the interval [0,2pi) a. x=pi, x=pi/2, x= 2pi/3 b. x=3pi/7, x=pi/2, x=2pi/3 c. x=3pi/7, x=3pi/2, x=3pi/2 d. x=pi, x=pi/2, x=3pi/2 
pre cal
cosA (7/25) pi < A < 3pi/2 sin B= 3/5 3pi/2 <B<2pi 
APCalculus
For the function y=2sin(x)cos^2(x) on [0, 2pi] find the following: Domain x and y intercepts Vertical asymptotes Horizontal asymptotes Symmetry F'(x) Critical numbers Increasing f(x) Decreasing f(x) Extrema F"(x) Possible points of … 
Trig
Find all solutions of the equation in the interval [0,2pi) 2 cos^2 xcos x = 0 2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) 1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong?