Pre-Cal(Please check)

posted by .

1) Find the Asymptotes:

y = -2 sec 2pi x

pi/2b and 3pi/2b

pi/2(2pi) = pi/4 and 3pi/4

Is this correct?

2) Find the period and asymptotes:

y = 1/2 sec pi x / 2

b = pi/2 I do not know how to find the period of asymptotes for this one. My original answer was 1 for the period and pi and 3pi for the asymptotes.

  • Pre-Cal(Please check) -

    No.
    y = -2 sec 2pi x

    when the argument is PI/2, or 3PI/2 of the secant function, it is inf

    2PI x =PI/2
    x= 1/4 or x= 3/4 is the x value of the asymptote.

    2. PIx/2=PI/2 or 3PI/2
    x=1 or x=3 is asympotes

    period? here is a neat way to memorize finding frequency and period.

    You should know this could also be written as sin w*x, where w(omega) is the angular frequency (2PI f) or 2PI/period

    So where we have sec PIx/2
    convert it PI*x/2=2PIx/2 * 1/period
    period= 1/f= 1

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Pre-Calculus-check answers

    State the period and phase shift of the function y=-4tan(1/2x + 3pi/8) a) 2pi, -3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, -3pi/8 Answer: d 2) What is the equation for the inverse of y=cos x+3: a) y=Arccos(x+3) b) y=Arccos x-3 c) y=Arccos …
  2. Math

    In the interval 0 </ x < 2pi, determine the equations of all asymptotes for the function y=tan x. a) x=0 b) x=pi/2 c) x=0, x=pi d) x=pi/2, 3pi/2
  3. Pre-Cal(Please check)

    Approximate the equation's solutions in the interval (0,2pi) sin2x sinx = cosx 2cos(x) (1/2-sin^2x) = 0 Then I got 3pi/2, pi/2, pi/6 and 5pi/6 Then I substituted 0-3 and got 3pi/2 , 5pi/2 , 9pi/2 , pi/2, pi/6, 7pi/6, 13pi/6 , 19pi/6 …
  4. trig

    I need to state the period and 2 consecutive asymptotes on the graph for the following questions. 1: y = -3 tan pi*x period: pi (?
  5. calculus

    given the graph of f(x) = x sinx, 0<=x<=2pi assuming that a quantity y changes at a rate of y' = xsinx, find by how much it will increase or decrease over 3pi/2 <= x <= 2pi the area under the graph from 0 to pi/2 is 1 the …
  6. TRIG

    I need to state the period and 2 consecutive asymptotes on the graph for the following questions. 1: y = -3 tan pi*x period: pi (?
  7. trig

    Solve cos x-1 = sin^2 x Find all solutions on the interval [0,2pi) a. x=pi, x=pi/2, x= 2pi/3 b. x=3pi/7, x=pi/2, x=2pi/3 c. x=3pi/7, x=3pi/2, x=3pi/2 d. x=pi, x=pi/2, x=3pi/2
  8. pre cal

    cosA (-7/25) pi < A < 3pi/2 sin B= -3/5 3pi/2 <B<2pi
  9. APCalculus

    For the function y=2sin(x)-cos^2(x) on [0, 2pi] find the following: Domain x and y intercepts Vertical asymptotes Horizontal asymptotes Symmetry F'(x) Critical numbers Increasing f(x) Decreasing f(x) Extrema F"(x) Possible points of …
  10. Trig

    Find all solutions of the equation in the interval [0,2pi) 2 cos^2 x-cos x = 0 -2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) -1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong?

More Similar Questions