# Calculus

posted by .

Evaluate the definite integral.
xe^(–x^2)dx from 0 to 6

• Calculus -

dx x e^-x^2

well d/dx (e^-x^2) = -2 x e^-x^2

so I will guess

(-1/2) e^-x^2 from 0 to 6

(-1/2) e^-36 - (-1/2)e^0

## Similar Questions

1. ### calculus

There are four integrals: 1) definite integral x/(1+x^4)dx b/w 0_infinity 2) definite integral (x^2)/(1+x^4)dx b/w 0_infinity 3) definite integral (x^3)/(1+x^4)dx b/w 0_infinity 4) definite integral (x^4)/(1+x^4)dx b/w 0_infinity Which …
2. ### calculus

There are four integrals: 1) definite integral x/(1+x^4)dx b/w 0_infinity 2) definite integral (x^2)/(1+x^4)dx b/w 0_infinity 3) definite integral (x^3)/(1+x^4)dx b/w 0_infinity 4) definite integral (x^4)/(1+x^4)dx b/w 0_infinity Which …
3. ### Calculus

Evaluate the definite integral of the transcendental function. the integral from 0 to 5 of (2^x +8)dx. I got 40+ 31/log(2)but that's wrong.
4. ### calculus solved

evaluate integral definite integral sign a=1 b=8 4(x^(2/3)+14)^3/((x^(1/3))) dx I get u= x^2/3 + 14 then du= 2/3 * x^(-1/3) dx 6 { u^4/4 | a=1 b=8 Then I get 3u^4/2 | a=1 b=8 2048-1.5= 2046.5 Is this correct. thank you all.
5. ### Calculus (urgent help)

consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: …
6. ### calculus

consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: …
7. ### calculus (please with steps and explanations)

consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: …
8. ### calculus

Evaluate lim (1³ +2³ +3³ +…+ n3)/n^4 n →∞ by showing that the limit is a particular definite integral and evaluating that definite integral.
9. ### Calculus

Evaluate the definite Integral Integral [0 to pi/4] cos(2x)sec^2(pi/4 sin(2x))dx
10. ### Math (Definite Integrals)

Sketch the region given by the definite integral. Use geometric shapes and formulas to evaluate the integral (a > 0, r > 0). r ∫ sqrt(r^2 - x^2) dx -r While I recognize that this looks similar to a circle function, I'm not …

More Similar Questions