Calculus
posted by <3 .
Evaluate the definite integral.
xe^(–x^2)dx from 0 to 6

dx x e^x^2
well d/dx (e^x^2) = 2 x e^x^2
so I will guess
(1/2) e^x^2 from 0 to 6
(1/2) e^36  (1/2)e^0
looks like about 1/2
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