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Calculate the molality of methanol in a solution prepared by dissolving 75.0 mL of methanol, CH3OH (d = 0.791 g/mL), in 150 g of ethanol, C2H5OH.

  • Chemistry -

    The definition is M = mols/kg solvent

  • Chemistry -

    My calculation
    0.791g/ml x 75ml /46 g/mol = 1.29M
    1.29M /0.15KG
    x= 0.116M

  • Chemistry -

    75mL*.791g/mL= 59.325g



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