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How many games are played in a women's soccer conference if there are eight teams and all teams play each other twice?

  • mathematics -

    8 (teams) x 7 (possible opponents of each team) / 2 = 28

    The division by two is necessary to avoid counting each game twice.

  • mathematics -

    I should have multiplied by 2 since each pair of teams plays twice. That makes the final number 56

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