Math
posted by Marla .
Four hundred people apply for three jobs. 130 of the applicants are women.
(a) If three persons are selected at random, what is the probability that all are women? (Round the answer to six decimal places.)
(b) If three persons are selected at random, what is the probability that two are women? (Round the answer to six decimal places.)
(c) If three persons are selected at random, what is the probability that one is a woman? (Round the answer to six decimal places.)
(d) If three persons are selected at random, what is the probability that none is a woman? (Round the answer to six decimal places.)

130 women, 270 men
a) Prob(3 women) = C(130,3)/C(400,3) = 357760/10586800 = .033793
b) Prob(2 women 1 man) = C(130,2)xC(400,1)/C(400,3) = .316810
can you see how I am doing those?
see if you answer the last two yourself.
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