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A 4 kg wooden block rest on a table. the coefficient of friction between the block and the table is .40. a 5kg mass is attached to the block by a horizontal string passed over a frictionless pulley of neglible mass what is the acceleration of the block when the 5 kg mass is released? what is the tension in the string during the acceleration?

  • physics -

    Force applied =5kgx9.8= 49N
    Force Against (friction)=4kgx9.8x.4=15.68

    first to find the Acceleration...

    49-15.69=Total Force= 33.32N

    F=MA F/M=A 33.32/9(both blocks)= 3.702m/ss

    Now for Tension..

    9.8-3.702=6.098

    6.098X5=30.49N=Tension

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