posted by KR .
Find algebraically the equation of the axis of symmetry and the coordinates of the vertex of the parabola whose equation is y= -2x-8x+3
-2x^2-8x = y -3 (suspect you meant
x^2 + 4x = -(1/2)y +3/2
x^2 + 4x + 4 = -(1/2)y +11/2
(x+2)^2 = -(1/2) (y-11)
vertex at (-2,11) axis is x = -2