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Find algebraically the equation of the axis of symmetry and the coordinates of the vertex of the parabola whose equation is y= -2x-8x+3

  • algebra -

    -2x^2-8x = y -3 (suspect you meant
    x^2 + 4x = -(1/2)y +3/2
    x^2 + 4x + 4 = -(1/2)y +11/2
    (x+2)^2 = -(1/2) (y-11)
    vertex at (-2,11) axis is x = -2

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