posted by Sarah .
The reaction of aqueous sodium bromide and aqueous lead(II) nitrate is represented by the balanced net ionic equation.
2Br-(aq) + Pb2+(aq) → PbBr2(s)
Give the balanced ionic equation for the reaction. Include the states.
This question is asking for the reverse of your previous posts; that is, the question wants you to take the net ionic equation given and make the molecular equation, then the ionic equation from that.
2NaBr(aq) + Pb(NO3)2(aq) ==> PbBr2(s) + 2NaNO3(aq), then
2Na^+(aq) + 2Br^-(aq) + Pb^+2(aq) + 2NO3^-(aq) ==> PbBr2(s) + 2Na^+2(aq) + 2NO3^-(aq)
Check my work to make sure all of the charges and (aq) marks are showing correctly.