A basketball team has won 50 games of 75 played. The team still has 45 games to play. How many of the remaining games must the team win in order to win 60% of all games played during the season?
50/75 games won= 25/75 games lost
45 more games. so to find the overall games played, add 75 and 45 to get 120.
60% of 120 is 72= games in total that they have to win
72-50= 22
Answer-22
75 + 45 = 120
0.6 * 120 = 72
72 - 45 = ?
you just do 72 - 45 =27? but what if that isn't an option like i was only left with these
20
21
22
25
30
To find out how many of the remaining games the team must win, we need to first calculate the total number of games the team will play in the entire season.
Given that the team has already played 75 games and still has 45 games to play, the total number of games in the season can be calculated by adding the number of games already played to the number of remaining games:
Total number of games in the season = Games already played + Remaining games
= 75 + 45
= 120
Now we need to determine how many games the team needs to win to achieve 60% of all games played in the season. We can do this by multiplying the total number of games by 60%:
Games to win = Total number of games * 60%
= 120 * 60%
= 72
Therefore, the basketball team must win 72 of the remaining 45 games in order to win 60% of all games played during the season. However, it is not possible to win a fraction of a game, so in this case, the team needs to win as many of the remaining games as possible, which is 45 games.