Three equal positive point charges of magnitude Q = 4.00ì C are located at three corners of a square of edge length d = 6.9 cm. A negative charge -14.00ì C is placed on the fourth corner. At the position of the negative charge, what is the magnitude of the electric field due to the three positive charges?
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What is the magnitude of the attractive force on the negative charge?
Do this the same way as your triangle problem
To find the magnitude of the electric field due to the three positive charges at the position of the negative charge, we can use the formula for electric field:
Electric field (E) = (1 / (4πε₀)) * (Σ(q_i) / r^2),
where Σ(q_i) represents the sum of all the charges and r is the distance between the charges. ε₀ is the vacuum permittivity, which is a constant.
In our case:
- The magnitude of each positive charge (q_i) is 4.00 μC.
- The distance between the charges (r) is the same for all three charges and is equal to the length of a side of the square (d = 6.9 cm).
To calculate the electric field at the position of the negative charge, we need to calculate the electric field due to each positive charge and then sum the individual electric fields:
1. Calculate the electric field due to one positive charge:
E_i = (1 / (4πε₀)) * (q_i / r^2)
2. Since there are three positive charges, calculate the total electric field:
E_total = 3 * E_i
To find the magnitude of the attractive force on the negative charge, we can use the formula for electric force:
Electric force (F) = q_negative * E_total,
where q_negative is the magnitude of the negative charge (-14.00 μC).
Substitute the given values into the formulas and calculate the answer.