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A skydiver is falling straight down at 60 m/s when he opens his parachute and slows to 8.3 m/s in 4.0 s. What is the average acceleration of the skydiver during those 4.0 s? (Assume that "up" is the positive direction.)

  • physics -

    Average acceleration
    = (velocity change)/(time)

    You are given the final and initial velocity. The V change is
    8.3 - 60 = -51.7 m/s

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