algebra
posted by Blake .
4x+12>4 and 3x25>13
Solution {xIx> ? }
I get so lost on these.

Try to get the x by itself, just like a=bx + c, where you would subtract c from both sides then divide both sides by b. since the coefficient for x on both are positive, you don't have to worry about the greater than/less than signs.
so for the first, subtract 12 from both sides then divide both sides by 4. it's the same concept for the other side. 
So I got x>2 for the first one and x>4 for the second one, now how does that fit into {xIx> ? }
Shouldn't it be just one number? 
4x+12>4 and 3x25>13
4x > 8 and 3x > 12
x > 2 and x > 4
so it looks like x > 4
write it in the notation asked for 
Ok, great thanks for the help both of you!
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