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What mass of NaOH is required to precipitate all the Fe2+ ions from 50.0 mL of 0.200 M Fe(NO3)2 solution?

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    Fe+2 + 2NaOH ==> Fe(OH)2 + 2Na^+
    How many moles Fe^+2 do you have? M x L = moles. So look at the equation and determine the moles of NaOH required to react with this many moles iron(II). Then grams NaOH = moles x molar mass.

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