Trig

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4tan^2u-1=tan^2u

3tan^2u=1

tan^2u=1/3

sq. root of (tan^2u)=sq. root of (1/3)

tanu=sq. root of (3)/3

tanu=sq. root of 1

Did I do this one right? If not, could you please show me the correct method??
Thanks!

  • Trig -

    I don't understand your last step.
    From tanu=sq. root of (3)/3
    The next step would be
    u = tan^-1[1/(sqrt3)]= 30 degrees
    (or 210 degrees)

    Your first steps are OK, until the last line.

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