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of a^2+b^2=2ab, prove log[(a+b)/2]=1/2(loga+logb)

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    systems of equations by graphing

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    I have made some editorial changes to reflect my interpretation of the question:
    "If a^2+b^2=2ab,
    prove log[(a+b)/2]=(1/2)(loga+logb)"

    If a²+b²=2ab, then
    (a-b)²=0 after factoring
    So we conclude that a=b

    Substituting a=b into the left-hand side of the equation:


    The right-hand side:


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