Precalculus
posted by Kate .
Factor completely
2(3x  5)3(2x + 1)^3 + (3x  5)^2 (3)(2x + 1)^2 (2)
I'm not really sure how to do this problem
I started out by rewriting this
6(2x + 1)^3(3x 5) + 6(3x  5)^2(2x + 1)^2
I am unsure were do go from here...

this was the answer in the back book. I do not see how to get this though
5(x + 3)(x  2)^2 (x + 1) 
6(2x + 1)^3(3x 5) + 6(3x  5)^2(2x + 1)^2
6(2x+1)^2(2x+1)(3x5) +6(2x+1)^2 (3x5)(3x5)
6(2x+1)^2(3x5) [ 2x+1 + 3x5 ]
6(2x+1)^2(3x5)(5x4)
So I do not see how to get that answer either.
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