A certain canoe was advertised as having an "800 pound capacity," meaning that it can hold at most 800 pounds. If four people plan to use the canoe and take 60 pounds of supplies, write and solve an inequality to find the average weight per person.

let x be the average weight per person

4x + 60 ≤ 800
x ≤ 185

(Wow, as a canoeist I must tell you this is an absurd question.
Four 185 pounders and gear in one canoe ???
What is this, a 17th century voyageur canoe? )

thanks pal

At most is represented by using the symbol ¡Ü, which stands for less than or equal to.

We can use any letter to represent the average weight for each person.

I will use W.

800 ¡Ü 4 times W and 60 pounds of supplies

800 ¡Ü 4W + 60

800 - 60 ¡Ü 4W

740 ¡Ü 4W

740/4 ¡Ü W

185 ¡Ü W

To find the average weight per person, we need to divide the total weight by the number of people using the canoe. Let's denote the average weight per person as 'x'.

Since there are four people planning to use the canoe and they are bringing supplies weighing 60 pounds in total, the total weight of the people and supplies is 4x + 60.

According to the canoe's capacity, this total weight must be at most 800 pounds. Therefore, we can write the inequality:

4x + 60 ≤ 800

To find the average weight per person, we need to solve this inequality. Let's do that:

4x ≤ 800 - 60
4x ≤ 740
x ≤ 740/4
x ≤ 185

So, the average weight per person must be less than or equal to 185 pounds.