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chemistry

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can you explain me how to do this question. any help would be much appreciated.

1) If 0.025 mol of COCl2(g) is placed in a one liter container at 400c, 16.0% of the CoCl2 is dissociated when equilibrium is established.

COCl2(g)-> Co(g)+Cl2(g)
calculate the value of K for the equilibrium at 400c.

  • chemistry -

    COCl2 ==> CO + Cl2

    K = (CO)(Cl2)/(COCl2)
    Start with 0.025 mol in a 1 L container makes it 0.025 molar in concentration.
    16% dissociates; therefore, (CO) = 0.025 x 0.16 = ??. (Cl2) = 0.025 x 0.16 = ??
    (COCl2) undissociated = 0.025 x 0.84 = ??.
    Plug in the values and calculate K.

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