Advanced Math

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log10x + log10(x+1)=1

In other words
log base 10 + log base 10(x+1)=1

I need to show it algebraically not using calculator

Thanks a lot !

  • Advanced Math -

    log10x + log10(x+1)=1
    log10[x(x+1)] = 1
    x(x+1) = 10^1
    x^2 + x - 10 = 0
    x = (-1 ± √41)/2

    but for log10 x, x > 0

    so x = (-1 + √41)/2

  • Advanced Math -

    thanks for you help and especially explanation

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