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A hollow steel tube of square cross section, whose outside dimension is 10cm on side and 5 mm thick, is loaded with compressive forces of 120 KN. What is the stress produced in the members.

  • mechanics -

    (Compressive force)/(Cross sectional area)

    The cross sectional area is (10 cm)^2 - (9 cm)^2 = 19 cm^2
    = 19*10^-4 m^2

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