70 J of work are done on the gas in the process shown in the figure.
What is V_f in cm^3 ?
I have a graph but I can't post it here.
My values are
W=70J
P=200kPa which is 200000Pa
I used the formula W=P(deltaV)
then to get deltaV you do: deltaV= W(P)
so i did 70J/200000pa= 2vf so i get 1.75e-4
is is right?
is it right?
It is true that Work = P*(delta V) (if P is constant during the process). How to you get from there to
delta V= W(P) ?
It seems to me that delta V = W/P
I can't be of much further help without seeing the figure. Sorry.
To calculate the final volume, V_f, in cm^3, we need to use the formula:
W = P * ΔV
Here, W is the work done on the gas, P is the pressure, and ΔV is the change in volume.
Given:
W = 70 J
P = 200 kPa = 200,000 Pa
To find ΔV, we rearrange the equation:
ΔV = W / P
Substituting the given values, we get:
ΔV = 70 J / 200,000 Pa = 0.00035 m^3
Since we want the answer in cm^3, we convert from m^3 to cm^3 by multiplying by 1,000,000:
ΔV = 0.00035 m^3 * 1,000,000 cm^3/m^3 = 350 cm^3
Therefore, the final volume, V_f, is 350 cm^3.
To find the final volume (V_f) in cm^3, you can use the formula W = P(deltaV), where W represents the work done, P is the pressure, and deltaV is the change in volume.
In this case, you have W = 70 J and P = 200 kPa = 200,000 Pa.
To find deltaV, you can rearrange the formula to solve for deltaV:
deltaV = W / P
Substituting the given values, we have:
deltaV = 70 J / 200,000 Pa
Performing the calculation, we get:
deltaV = 3.5 x 10^(-4) m^3
To convert this to cm^3, you need to multiply by the appropriate conversion factor. Since 1 m^3 = 1,000,000 cm^3, you can use this conversion factor:
deltaV = 3.5 x 10^(-4) m^3 * (1,000,000 cm^3 / 1 m^3)
Simplifying, you find:
deltaV = 350 cm^3
Therefore, the final volume (V_f) in cm^3 is 350 cm^3, which is different from the value you calculated (1.75 x 10^(-4) cm^3). Please verify your calculations and make sure you use the correct units for consistent results.