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Identify the limiting reactant and determine the mass of the excess reactant remaining when 7.00 g of chlorine gas reacts with 5.00 g of potassium to form potassium chloride.

  • chemistry -

    2molK + 1molClgas create 2molKCl
    nK/nClgas=2/1
    5/39:7/31=1.3
    so Cl gas excess
    mClgas(excess) = 7-(5*71/78) = 2.45g

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