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I'm trying to find the cosecant of 11 pi/6. The answer is -2, but I'm not sure where this came from. I thought You would flip the sine value which was sq. root of 3/2, making it 2/sq. root of three, which would then become sq. root of -6 over 3 or sq. root of -2. Why isn't there a sq. root sign? Thanks!!!

  • Trigonometry -

    11pi/6 is just pi/6 short of 2pi
    so csc 11pi/6
    = csc (-pi/6)
    = -csc pi/6
    = -1/sin pi/6
    = -1/(1/2), [sin 30ยบ = sin pi/6 = 1/2]
    = -2

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