Trigonometry
posted by Delia .
I'm trying to find the cosecant of 11 pi/6. The answer is 2, but I'm not sure where this came from. I thought You would flip the sine value which was sq. root of 3/2, making it 2/sq. root of three, which would then become sq. root of 6 over 3 or sq. root of 2. Why isn't there a sq. root sign? Thanks!!!

11pi/6 is just pi/6 short of 2pi
so csc 11pi/6
= csc (pi/6)
= csc pi/6
= 1/sin pi/6
= 1/(1/2), [sin 30ยบ = sin pi/6 = 1/2]
= 2
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