posted by Z32 .
Evaluate the indefinite integral:
x^2 / (3-4x^3)^6
I got -1/(60(4x^3-3))^5 but it's not right.
Your answer is almost right except that some parentheses are in the wrong places.
Verify the parentheses.
Also, if the question asks to simplify the answer, you may be expected to remove the negative sign by switching the order of the terms in the denominator (to (3-4x³).
Unfortunately computer answers are sometimes quite one-track minded.
The parenthesis are in the wrong spot? I still can't figure it out.
Oh, okay. I got it.